A Question about Kirchoff's Voltage Law

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SUMMARY

This discussion clarifies the application of Kirchoff's Voltage Law (KVL) in circuit analysis, specifically addressing the treatment of voltage sources in a clockwise loop. The voltage source E1 is considered a voltage rise, while E2 is treated as a voltage drop due to the direction of current flow. The key takeaway is to consistently assign signs based on the chosen loop direction, ensuring that the sum of voltage rises equals the sum of voltage drops around the circuit.

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bibo_dvd
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Hello Guys

My Question about Kirchoff's Law is : why in this Example
we considered that E2 is a Voltage Drop not a Voltage Rise ??

i mean why we didn't say that : +E2-V1-V2+E2=0 ?


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and Thanks Guys :)) !
 
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It's because the loop has a direction. In this case, the loop is clockwise, making E1 positive but E2 negative.
 
Pick a direction for your analysis. Assign a sign to all the voltage rises, and the opposite sign to the voltage drops. The sum of all the voltage rises =the sum of all the voltage drops around the circuit.

In your example, the current loop is clock wise, so the current flows into the negative side of E1 (voltage rise), and into the positive side of E2 (voltage drop).
 

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