A question about Poisson process (waiting online)

ssyldy
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Hey guys, I encounter a question (maybe a silly one )that puzzles me. Nt is a Poisson process and λ is the jump intensity.Since the quadratic variation of Poisson process is [N,N]t=Nt, and Nt2-[N,N]t is a martingale, it follows that E[Nt2]=E[[N,N]t]=λ*t. On the other hand, the direct calculation of E[Nt2] can be found in https://proofwiki.org/wiki/Variance_of_Poisson_Distribution, which indicates E[Nt2]=(t*λ)2+t*λ. The two results are different. I really appreciate it if somebody can help me.
 
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It would help to know the context of that calculation and the meaning of the individual symbols.
 
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Nt is a Poisson process and λ is the jump intensity.Since the quadratic variation of Poisson process is [N,N]t=Nt, and Nt2-[N,N]t is a martingale, it follows that E[Nt2]=E[[N,N]t]=λ*t. On the other hand, the direct calculation of E[Nt2] can be found in https://proofwiki.org/wiki/Variance_of_Poisson_Distribution
 
ssyldy said:
Hey guys, I encounter a question (maybe a silly one )that puzzles me. Nt is a Poisson process and λ is the jump intensity.Since the quadratic variation of Poisson process is [N,N]t=Nt, and Nt2-[N,N]t is a martingale, it follows that E[Nt2]=E[[N,N]t]=λ*t. On the other hand, the direct calculation of E[Nt2] can be found in https://proofwiki.org/wiki/Variance_of_Poisson_Distribution, which indicates E[Nt2]=(t*λ)2+t*λ. The two results are different. I really appreciate it if somebody can help me.
It looks like someone has confused the second moment with the variance.
 
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mathman said:
It looks like someone has confused the second moment with the variance.
Hi dude, seems like you know the answer. Could you explain?
 
ssyldy said:
Hi dude, seems like you know the answer. Could you explain?
General formulas for a random variable X:
second moment: E(X^2)
variance: E(X^2)-(E(X))^2
 
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mathman said:
General formulas for a random variable X:
second moment: E(X^2)
variance: E(X^2)-(E(X))^2
Yeah, I know that. But my question is, why would I get two different results of E[Nt2] using two different methods?
 
ssyldy said:
Yeah, I know that. But my question is, why would I get two different results of E[Nt2] using two different methods?
My guess - a mistake in the derivation. E[N_t^2]=\lambda t looks wrong (unless the mean=0). It is the variance.
 
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