A question about strain in graphene

  • Thread starter Thread starter barana
  • Start date Start date
  • Tags Tags
    Graphene Strain
barana
Messages
17
Reaction score
0
Dear forum people
The new position of the carbon atoms under uniaxial strain r in the framework of elastic theory is shown by the following equation:
ri'=(I+ε).ri
in which ri and ri' are the position of the carbon atoms before and after the strain is applied, respectively.
I is the unit matrix and ε is the strain tensor which is attached.
I can't calculate ri' .
For example:

δ1=a(√3/2,-1/2) δ2=a(0,1) δ3=a(-√3/2,-1/2)
|δ1|=1+(3/4)ε11-(√3/2)ε12+(1/4)ε22
|δ2|=1+ε22
|δ3|=1+(3/4)ε11+(√3/2)ε12+(1/4)ε22

Can help me?
How calculate |δ1|,|δ2|,|δ3|?
 

Attachments

Physics news on Phys.org
Are you uncertain of how to do a matrix addition and then a matrix x vector?
 
jedishrfu said:
Are you uncertain of how to do a matrix addition and then a matrix x vector?
I don't know how obtained |δ1|,|δ2|,|δ3|.
δ1=( √3/2*a(1-ε11)-a/2*ε12 ; √3/2a*ε21-a/2*(1-ε22))
According to δ1, |δ1| not equal with |δ1| above maintained.
 
From the BCS theory of superconductivity is well known that the superfluid density smoothly decreases with increasing temperature. Annihilated superfluid carriers become normal and lose their momenta on lattice atoms. So if we induce a persistent supercurrent in a ring below Tc and after that slowly increase the temperature, we must observe a decrease in the actual supercurrent, because the density of electron pairs and total supercurrent momentum decrease. However, this supercurrent...
Hi. I have got question as in title. How can idea of instantaneous dipole moment for atoms like, for example hydrogen be consistent with idea of orbitals? At my level of knowledge London dispersion forces are derived taking into account Bohr model of atom. But we know today that this model is not correct. If it would be correct I understand that at each time electron is at some point at radius at some angle and there is dipole moment at this time from nucleus to electron at orbit. But how...
Back
Top