A question on matrices properties

transgalactic
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there is some property of matrices that i forgot
that says that for some kind of matrices there is a given number

that if we will put the given martices to the power of this given number
it will get the zero matrices

for example
0 a
a b

in the power of 3 will change for the first time to
0 0
0 0

what are the laws for this number 3

how do i know the number by looking at the given matrices
 
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Such a matrix A is called "http://planetmath.org/encyclopedia/NilpotentMatrix.html ", and the smallest natural number n such that An=0 is usually called the "index of nilpotence". Try googling for information -- you'll find a lot.
 
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i read about them
i understood the transformation
of each step

but i was told the the number comes from the size of the given matrices
which is not true in the case that i showed

the only way that i can find out the number is by practicly
step by step multiplying the matrix by itself.

is there an yeasier way??
 
I'm not familiar with any easier general method.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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