A quick distance/time question.

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AI Thread Summary
To determine the vertical height of the aircraft, the round trip time of the radar pulse, 1.28*10^-4 seconds, should be halved to find the one-way travel time. The distance can then be calculated using the formula d=vt, where 'v' is the speed of the radar pulse. After finding the hypotenuse, the vertical height can be derived using the sine function with the angle of elevation of 22.0 degrees. The discussion also humorously notes a misunderstanding of the term "theta." The focus remains on applying the correct physics principles to solve the problem.
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Homework Statement


A radar pulse projected at an angle of elevation of 22.0 degrees is reflected from an aircraft and returned. If the pulse takes 1.28*10^-4s to make the round trip, then the vertical height of the aircraft is? (Height of radar transmitter/receiver can be ignored)




Homework Equations





The Attempt at a Solution



I know how to do it, just use d=vt to find the hyp and then use sin feta to find vertical height.

But for time do i use 1.28*10^-4s? or use half of that since that time is the round trip?
 
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I woud do it that way, you have the right thinking... you can also use that time and get the total distance and divide that by 2...
 
I thought feta was a type of Greek cheese.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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