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A quick projectile motion problem. Please help me! Thanks!

  1. Sep 26, 2008 #1
    A marble is thrown horizontally with a speed of 23.4 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 61.8 ° with the horizontal. From what height above the ground was the marble thrown?

    So far I have found Ay= -9.8, Ax= 0, Vox=23.4, Voy=0. And Vx=23.4 (im not sure if I need that).

    Any help will be greatly appreciated! Thank you!
     
  2. jcsd
  3. Sep 26, 2008 #2
    remember velocity is a vector too and can be treated like distances. Draw a triangle to represent the x and y velocities. if you set it up right you should be able to use the Tan funtion to find the y velocity component. I'm sure you can figure it out from there
     
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