A marble is thrown horizontally with a speed of 23.4 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 61.8 ° with the horizontal. From what height above the ground was the marble thrown? So far I have found Ay= -9.8, Ax= 0, Vox=23.4, Voy=0. And Vx=23.4 (im not sure if I need that). Any help will be greatly appreciated! Thank you!