Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

A quick question on Irrational powers

  1. Jun 1, 2007 #1
    I wish to prove that for f(x)=x^x, its domain is: {x E R, x > 0}U{xEZ,x<0}.
    I reevaluated to e^(xlnx), obviously that did not help. Is there an algorithm/formula/something that can evaluate irrational powers, so that it can help me with this?
     
  2. jcsd
  3. Jun 1, 2007 #2
    From what I understand of your question, you are following a misleading path. The function x^x, when x < 0, is defined at every x = a/b (reduced fraction) such as that b is not an even number. About irrational numbers, the question is ambiguous. For the negative irrationals, what does the expression x^x even mean? For positive irrationals, x^x can be expressed as an infinite series and can be approximated. A negative irrational could be approximated as x = a/b with the condition that b is and odd number and hence we get an approximation of x^x, but it can also be approximated as a/b in which b is an even number and hence yield an imaginary approximation. I have to put much thinking into it, but from this my very quick assumption is that x^x for negative irrationals is an absurd expression.
     
  4. Jun 1, 2007 #3
    :P I only just realised that I did not define b can be odd. Anyway I require a technique to evaluate powers so that I can personally show that irrational numbers below zero cannot be part of the domain of x^x.
     
  5. Jun 1, 2007 #4
    Have you tried re-evaluating it to [itex]e^{x ln(abs(x))}[/itex]? It evaluates to the same thing, except of course that it has a "larger" domain than x^x.

    Edit: Actually, I rescind this statement--it's not true. I think it might still be helpful for evaluating [itex]e^{x ln(x)}[/itex], though, so I'll leave it up.
     
    Last edited: Jun 1, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: A quick question on Irrational powers
  1. Quick Question (Replies: 2)

  2. Quick question (Replies: 3)

  3. Quick Question (Replies: 2)

  4. A quick question. (Replies: 4)

Loading...