A rocket moves through outer space at 11,000 m/s.

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To calculate the time required for a rocket traveling at 11,000 m/s to reach the Moon, divide the distance of 380,000 km by the speed, resulting in approximately 34.5 minutes. For the rock thrown upwards, it reaches a peak velocity of zero before falling back, and using the formula for free fall, it strikes the ground at a velocity of about 24.5 m/s. The momentum of a 30.0 kg shell fired at 500 m/s is calculated to be 15,000 kg·m/s. To find the forward force needed for a 60.0 kg person to accelerate at 1.00 m/s², apply Newton's second law, resulting in a force of 60 N. Accurate unit conversions and understanding of physics principles are essential for solving these problems effectively.
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A rocket moves through outer space at 11,000 m/s. At this rate, how much time would be required to travel the distance from Earth to the Moon, which is 380,000 km?

A rock thrown straight up climbs for 2.50 s, then falls to the ground. Neglecting air resistance, with what velocity did the rock strike the ground?

What is the momentum of a 30.0 kg shell fired from a cannon with a velocity of 500 m/s?

What forward force must the ground apply to the foot of a 60.0 kg person to result in an acceleration of 1.00 m/s²?
 
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For your first question you need to make sure that everything is in the right units. 1 mile is equal to around 1.6 kilometres.

You need to show you have made some attempt first.
 
Once you have converted you can use...

speed=\frac{distance}{time}
 
for the 2nd question try listing out what is already given to you like the acceleration, time, and velocity final and remember the fact that at the top of the peak the velocity is zero and the velocity at the moment you release the rock is the same as before it hits the ground.

hope it helps with the work
 
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