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A Rotation with Translation Movement is standalone natural phenomenon.

  1. Sep 13, 2009 #1
    Please look into this site
    http://knol.google.com/k/alex-belov/paradox-of-classical-mechanics-2/1xmqm1l0s4ys/9#


    The experiment 2 animations

    This is animation based on classical mechnics laws
    http://mysite.verizon.net/vze27vxm/sim.gif



    This is animation based on theory of standalone rotation with translation movement.
    http://mysite.verizon.net/vze27vxm/movie2.gif



    The Natural Experiment 2.

    I made 3 successful experiments with 2 pencils.
    On all these experiments pencils with rotation movement have lower velocity than pencils without rotation.

    The theory is CORRECT.
    The simulator is WRONG.

    Materilas:
    2 pencils and thin rubberband 3.5'' from Staples store.

    The rubberband is repulsing 2 objects(2 pencils). Two their parts have opposite velocities to each other. After initial action the rubberband has velocity zero. The rubberband mass much less then pencil mass.

    Here is some snapshots which shows experiment dynamic.
    http://knol.google.com/k/-/-/1xmqm1l0s4ys/h6o9ht/1%20(1).jpg [Broken]
    http://knol.google.com/k/-/-/1xmqm1l0s4ys/h6o9ht/2%20(1).jpg [Broken]
    http://knol.google.com/k/-/-/1xmqm1l0s4ys/h6o9ht/3%20(1).jpg [Broken]
    http://knol.google.com/k/-/-/1xmqm1l0s4ys/h6o9ht/4%20(1).jpg [Broken]

    The rotation with translation movement is standalone natural phenomenon. It should have it's own law of momentum conservation.
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Sep 14, 2009 #2

    Doc Al

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    Staff: Mentor

    In your second example, you make the claim that angular momentum is not conserved. That's incorrect. All you've shown is that the angular momentum of each object about its own center of mass is not conserved. Nothing wrong with that. One object receives a torque about its center of mass, while the other doesn't.

    If you calculate the total angular momentum of the system, you'll see that angular momentum is conserved. (When you calculate the total angular momentum of each object, use the same reference point and don't neglect the angular momentum due to the motion of the center of mass.)
     
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