Finding the Sum of a Series with Justification | 3 + 2 + 4/3 + 8/9 + 16/27 + ...

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Homework Statement



Find the sum of the sereis 3 + 2 + 4/3 + 8/9 + 16/27 + ... and provide justification for your work.

Homework Equations





The Attempt at a Solution



I first thought that this was true

inf
sigma 2^k/3^(k-1)
k=0

This would be the correct series if we let the first term given in the series, given in the statement problem be the zeroth term and so on. I however had no idea how to find the sum of this series because of the different powers that occur in the numerator and denominator... thanks for any help
 
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Hint: write 3k-1 as (3k)(3-1).

ehild
 
*bangs head into desk* lol thanks
 
Not mentioned above is the fact that your series is a geometric series with ratio r = 2/3 and first term a = 3. Your text probably presented geometric series and arithmetic series before going on to other types of series.
 
Ya my text does and you I figured this problem out and couldn't believe that I didn't see that
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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