A simple Complex Analysis Mapping

NewtonianAlch
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Homework Statement


http://img684.imageshack.us/img684/779/334sn.jpg


The Attempt at a Solution



The first part was fairly straightforward, solve for z + 1, and then get w in terms of u + iv, rationalise the denominator, and then we get (x,y) in terms of u and v, which we substitute back into the equation of the line, and get it into the form of an equation of a circle.

The next part is not as obvious for me, I tried the same method, but I couldn't rationalise the denominator, I'm assuming the circle is shifted somehow because of the 2, but I'm not sure.
 
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NewtonianAlch said:

Homework Statement


http://img684.imageshack.us/img684/779/334sn.jpg


The Attempt at a Solution



The first part was fairly straightforward, solve for z + 1, and then get w in terms of u + iv, rationalise the denominator, and then we get (x,y) in terms of u and v, which we substitute back into the equation of the line, and get it into the form of an equation of a circle.

The next part is not as obvious for me, I tried the same method, but I couldn't rationalise the denominator, I'm assuming the circle is shifted somehow because of the 2, but I'm not sure.

If you can't do it with complex numbers, switch to vectors.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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