A simple Fluid Dynamics/Pressure HW question

[SnakeDoc]

Homework Statement

A piston of cross-sectional area a is used in a hydraulic press to exert a small force of magnitude f on the enclosed liquid. A connecting pipe leads to a larger piston of cross-sectional area A (the figure). If the piston diameters are 3.63 cm and 50.7 cm, what force magnitude on the small piston will balance a 41.8 kN force on the large piston?

Homework Equations

P=F/A

The Attempt at a Solution

So I'm pretty sure I'm doing this right especially since we did a similar one in class so I think it might just be a math error here's what I did.

For the smaller side P_s = F_s/a_s

For the larger side P_b = F_b/A_b

P_s = P_b

F_s/a_s = F_b/A_b

Solve for F_s
F_s = F_b/A_b * a_s

Plug in values (F_b 41.8kN = 41800N) (A_b 50.7cm =.507m) (a_s 3.63cm = .0363m)

F_s = (41800/.507)*.0363 = 2992.78N WileyPlus says its wrong though, so did I make a mistake?

 

[paisiello2]

For some reason you plugged in the diameters instead of the areas.

 

[SnakeDoc]

For some reason you plugged in the diameters instead of the areas.

I guess I did. I didn't even notice it said diameters thanks. I must remember to read more thoroughly next time.