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Let us imagine that there is a long train that moves with speed of v=sqrt(3/4)*c

For v=sqrt(3/4)*c

gamma=2

The clocks are synchronized when the railway engine meets the observer in reference frame.

When a one unit of time in reference frame has passed (t=1), then the observer

looks on the car that is at position:

x = sqrt(1/3)

Then the oberver is supprised, because the clock in the car shows the same time as its clock:

t' = gamma(t-v/c2 * x)

gamma=2

t=1

x=sqrt(1/3)

t'=2(1-sqrt(3/4)*sqrt(1/3) = 1

Can anybody explain what that it means?