A straight line in the complex plane

AI Thread Summary
The discussion revolves around determining whether the equation w - w* = (s - t*)z + (t - s*)z* + r - r* = 0 represents a complex straight line, given that w = sz + tz* + r = 0 defines one. Participants analyze the forms of both equations, noting that w + w* results in a complex straight line equation, while w - w* introduces an imaginary component. The confusion arises from the expectation that both forms should align with the standard complex straight line equation format. Ultimately, the participants seek clarification on the conditions under which these equations can be classified as complex straight lines.
rajeshmarndi
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Homework Statement
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0, is a straight line. Then couldn't find how does
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0, is also a straight line.
Relevant Equations
w = sz+tz*+r=0
sz+tz*+r=0=say w

so w* = s*z* + t*z + r*=0

Now ,
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0
= p*z + pz* + k = 0...eq(1) ( k is a constant or twice real part of w)
which is in complex straight line equation form i.e ab* + a*b + c = 0 ( a,b are complex number and c a real number.

Now, again,
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0

I couldn't understand, in the solution, how this is also termed as a complex straight line like eq(1).
Since when this is worked out, it comes to be as,

q*z - qz* + id = 0 ( since r-r* will give imaginary number)

This is not in the form of a complex straight line equation.

Thanks.
 
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rajeshmarndi said:
sz+tz*+r=0=say w

so w* = s*z* + t*z + r*=0

Now ,
w+w* = (s+t*)z + (t+s*)z* + r+r* = 0
= p*z + pz* + k = 0...eq(1) ( k is a constant or twice real part of w)
which is in complex straight line equation form i.e ab* + a*b + c = 0 ( a,b are complex number and c a real number.

Now, again,
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0

I couldn't understand, in the solution, how this is also termed as a complex straight line like eq(1).
Since when this is worked out, it comes to be as,

q*z - qz* + id = 0 ( since r-r* will give imaginary number)

This is not in the form of a complex straight line equation.

Thanks.

What, in plain language, is the statement of the problem? Is it "prove that w+w*=0 describes a straight line in the complex plane"? Is it something else? I cannot figure out what you want.
 
Ray Vickson said:
What, in plain language, is the statement of the problem?
I want to know,
given w= sz+tz*+r=0

Is
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0
also a complex straight line?

[edit: r,s,t are non-zero complex number and z=x+iy (x,y ε R) ]
 
Last edited:
rajeshmarndi said:
I want to know,
given w= sz+tz*+r=0

Is
w-w* = (s-t*)z + (t-s*)z* + r-r* = 0
also a complex straight line?

[edit: r,s,t are non-zero complex number and z=x+iy (x,y ε R) ]

Write ##w## in real terms, and expand it out to see what you get. That is, write ##s=s_1+i s_2, t = t_1+i t_2, r = r_1+i r_2## and ##z = x + i y##.
 
Ray Vickson said:
Write ##w## in real terms, and expand it out to see what you get. That is, write ##s=s_1+i s_2, t = t_1+i t_2, r = r_1+i r_2## and ##z = x + i y##.
##w## becomes,

##w = [(s_1+t_1)x + (t_2-s_2)y] + i[(s_2+t_2)x + (s_1-t_1)y+r_2]=0##

So the real terms of ##w## is ## [(s_1+t_1)x + (t_2-s_2)y]=0##
 
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