Understanding SHM: Velocity of a Mass on a Spring at Max Displacement

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In simple harmonic motion (SHM), when a mass on a spring reaches its maximum displacement from equilibrium, its instantaneous velocity is zero. This is because, at this point, the mass must stop momentarily before reversing direction. The discussion clarifies that just before reaching maximum displacement, the velocity is positive, and just after, it becomes negative, indicating a change in direction. The consensus is that the speed at the extremes of position is indeed zero. Understanding this concept is crucial for grasping the dynamics of SHM.
Dx
I am curious to know that if a mass on a spring undergoes SHM. when the mass is at its MAX displacement from equilibrium, its instantaneous velocity is what?
is it zero!

can someone explain?
Dx :wink:
 
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Well, just before the mass hits the max displacement, the velocity is +deltaV, and just after it is -deltaV. You have to go through zero to get from + to -.
 
Okay!

Dx scratches his head.
I said at MAX displacement that deltav is + or - Max but my teacher says I am wrong. It must be less than max but not zero as youve kinda explained, i think
Dx :wink:

Right?
 
You had it right the first time: The speed at the extrema of position is zero.

If you are moving this way ----->
and then this way <-----

then at some point you had to stop[/color] and turn around.
 
Kool

Hello,

Thanks!
Dx :wink:
 
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