About heat question which one is right?

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When 1 kg of 0 degree Celsius ice is placed in 0 degree Celsius cold water, both the temperature of the ice and the water remain unchanged if the system is isolated. The phase transition allows both ice and water to coexist at this temperature without changing their thermal states. Energy is required to melt the ice, but this energy does not lower the water's temperature due to the equilibrium of the system. The discussion emphasizes that mixing substances at the same temperature does not alter their temperatures, adhering to the principles of thermodynamics. Thus, the total internal energy remains unchanged in this scenario.
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It is given that:

1 kg of 0 degree celsius ice is put into a cup of 0 degree celsius cold water.

is the temperature of the ice and the water remains unchanged?

or the total internal energy remains unchanged?

THX!
 
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new hand said:
0 degree celsius cold water.
I don't think it will be cold water anymore
 
new hand said:
It is given that:

1 kg of 0 degree celsius ice is put into a cup of 0 degree celsius cold water.

is the temperature of the ice and the water remains unchanged?

or the total internal energy remains unchanged?

If the system is isolated, both are true.
adjacent said:
I don't think it will be cold water anymore
Why? At the temperature of the phase transition, both phases coexist.
 
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DrClaude said:
Why? At the temperature of the phase transition, both phases coexist.

Oh, I see.:shy: Thanks
 
oh I forget to say
Assume there is no energy transfer between the mixture and the surroundings.
 
But I think in this way,

Even if the ice melts, the energy released by the ice is not enough to lower the temperature of the water. And the temperature of the ice cannot rise because there is no heat transfer.
 
new hand said:
Even if the ice melts, the energy released by the ice is not enough to lower the temperature of the water.
:confused: You need to add energy to ice to transform it into liquid water.
 
So, will the temperature remain unchanged?
 
new hand said:
So, will the temperature remain unchanged?
Yes, unless you want to violate the 0th law of thermodynamics.

Absent any chemical reaction (including dissolution), mixing two things of the same temperature together can only result in something at the same temperature.
 

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