About Solvable/Unsolvable ODEs

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In my class, I learned about a First-order ODEs,

and solvable and unsolvable.

example in case solvable ODEs)
dy/dt=t/y
dy/dt=y-t^2

example in case unsolvable ODEs)
dy/dt=t-y^2

but , i don't know how distinguish those.

please, teach ME! : ( as possible as easily !
 
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The question is not about whether the equation has a solution. It's about how easy it is to find the solution. The equation ##\frac{dy}{dt}=\frac{t}{y}## is separable and is easy to solve by multiplying both sides with ##ydt## and integrating the resulting equation ##ydy=tdt##. The equation ##\frac{dy}{dt}=y-t^{2}## can be solved by first multiplying both sides with the integrating factor ##e^{-t}##, and then using the derivative of product rule and integrating the resulting equation ##\frac{d}{dt}\left(e^{-t}y\right)=t^{2}e^{-t}##.

For the nonlinear and non-separable equation ##\frac{dy}{dt}=t-y^{2}##, there is no similar simple method of solution. There does exist a solution, but it must be written in terms of special functions called Bessel functions. Do you know how to solve DE:s with WolframAlpha or Mathematica?
 
Oh,! I got it! Thanks : )
 
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Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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