Understanding Spatial Resolution: Calculating and Applying θmin=1.22λ/D

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The discussion focuses on calculating spatial resolution using the formula θmin=1.22λ/D, with an example calculation yielding θs=24.4μm. Participants clarify that spatial resolution is related to angular resolution and should be expressed in appropriate angular units, specifically micro-radians (μrad). The arc length of a circle, defined by the angle of angular resolution, is discussed, with the focal length of the lens being identified as the radius (r) for this calculation. The importance of understanding the relationship between spatial and angular resolution is emphasized. Overall, the conversation aims to clarify how to accurately calculate and interpret spatial resolution in optics.
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Homework Statement


擷取1.PNG


Homework Equations


θmin=1.22λ/D

The Attempt at a Solution


(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??
 
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kenok1216 said:

Homework Statement


View attachment 99604

Homework Equations


θmin=1.22λ/D

The Attempt at a Solution


(a)θmin=1.22λ/D
(b)θs=1.22(600nm)/30mm=24.4μm but what is spatial resolution and how to calculate it??
That answer should be in units appropriate for an angle, certainly not μm .
 
kenok1216 said:
what is spatial resolution and how to calculate it??
It's related to the angular resolution. You can think of the spatial resolution as the arc length of a circle subtended by the angle of angular resolution.
 
SammyS said:
That answer should be in units appropriate for an angle, certainly not μm .
sor, it is μrad
 
kenok1216 said:
sor, it is μrad
Yes.
 
blue_leaf77 said:
It's related to the angular resolution. You can think of the spatial resolution as the arc length of a circle subtended by the angle of angular resolution.
s=rθ, so what is r is this question?object distance? focal length?image distance?
 
kenok1216 said:
s=rθ, so what is r is this question?object distance? focal length?image distance?
About the circle I was talking about, you can assume it to be centered at the center of the lens and since your image is located at the focal plane, the arc length of interest must touch the focal plane. What will r be?
 
blue_leaf77 said:
About the circle I was talking about, you can assume it to be centered at the center of the lens and since your image is located at the focal plane, the arc length of interest must touch the focal plane. What will r be?
Focal lenght?
 
kenok1216 said:
Focal lenght?
Yes.
 
  • #10
SammyS said:
Yes.
Thank
 

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