- #1
cavery4
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At what depth beneath the surface of a lake is the absolute pressure 6 times the atmospheric pressure of 1.01 x 105 Pa that acts on the lake's surface?
pressure = density * g * h
I thought to multiply 6 * 1.10 X 10^5 pa. Then divide that answer by 1000 kg/m3 (density of water, right?) * 9.8 m/s/s.
This was marked wrong my webassign.
Can someone help me figure out what I did wrongly?
Thank you.
pressure = density * g * h
I thought to multiply 6 * 1.10 X 10^5 pa. Then divide that answer by 1000 kg/m3 (density of water, right?) * 9.8 m/s/s.
This was marked wrong my webassign.
Can someone help me figure out what I did wrongly?
Thank you.