- #1
Tamis
- 8
- 0
I'm given [itex]1-a\cdot e^{-i\cdot 2 \pi f}[/itex]. The squared absolute value apparently is [itex]|1-a\cdot e^{-i\cdot 2 \pi f}|^2=1+a^2-2acos(2 \pi f)[/itex].
Sadly the awnser doesn't show the steps of this derivation. I have tried many times to derive it my self but have not been able to do so. I feel like i am missing the obvious, does anyone care to show me how it's done?
Sadly the awnser doesn't show the steps of this derivation. I have tried many times to derive it my self but have not been able to do so. I feel like i am missing the obvious, does anyone care to show me how it's done?