Abundancy of Uranium 235 when the earth was formed.

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Homework Statement


The Earth is about 4.5 billion years old. If 235U is 0.65% abundant today, how abundant was it when the Earth formed? Note, in this case abundancy is defined as the ratio of Uranium 235 to Uranium 238

Homework Equations


R=N(lambda)
N=N0e^-lambda(t)
Half Life = ln(2)/lambda

The Attempt at a Solution


I am really unsure how to do this problem. I tried reworking the above equations but I was not able to get the correct answer. I need a little help getting started.
 
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In your second equation, you can divied by N0 to give N/N0. What would this quantity represent? Think about the total range of values this quantity could take on. Can N be negative? Can N>No?
 
Well, N/N0 would be the probability that a nucleus has decayed in the given period of time which in this case would be -4.5billion years if we take t=0 to be the present. And can't N be larger than N0 if we are going back in time?
 
ok, so I've worked it up to the point where I have the new abundancy = .0065e^(lambda238-lambda235)*4.5billion years but it's wrong. How can i fix this?
 
Got it wrong so now I got an 80 on my HW. Thanks for nothing.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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