AC circuit analysis involving resistors and inductors

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To solve the AC circuit involving resistors and inductors, start by rearranging the components for clarity, placing capacitors next to their respective resistors. Convert inductors and capacitors to their reactance values using the formulas XL = ω⋅L and XC = -1 / ω⋅C. Represent the impedances as complex numbers in the form Z = R + Xj. Transform the Y configuration to a delta to eliminate floating nodes, allowing for easier calculations. Finally, calculate the currents using the converted voltage and phase values.
Franklie001
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Summary:: Hi anyone can explain me how to solve this circuit, finding the current I2 and I1?
Really don't know where to start Thanks

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Is this school work?
Make it easier to recognise the circuit by first migrating C1 to be next to R1. Then C2 to be next to L2. Make the base line ground.

Convert L and C to reactance. Then write the three impedances composed of series R, L & C as complex numbers, Z = R + Xj .

Transform Y to delta. https://en.wikipedia.org/wiki/Y-Δ_transform
Now there are no floating nodes.
You have voltage and phase, convert them to complex.
Work out the currents from there.
 
Hi thanks for your help, yes it's a coursework from uni
How do i convert the L and C to reactance by the way?

Should i have to convert also the voltages as complex number too?

Thank you
 
Franklie001 said:
How do i convert the L and C to reactance by the way?
XL = ω⋅L
XC = -1 / ω⋅C
ω=2⋅π⋅f
 
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