Engineering Understanding Circuit Components: Capacitor, Inductor, Resistor

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A pure capacitor and a pure inductor do not consume electrical energy because they store energy temporarily, while a pure resistor dissipates energy as heat. In an inductor, the current lags the voltage by 90 degrees, leading to a relationship where the instantaneous power is zero over a complete cycle, resulting in no net energy consumption. For a capacitor, the current leads the voltage by 90 degrees, and similarly, the average power over a cycle is also zero. The equations for power in both reactive components show that they do not contribute to net energy consumption, contrasting with resistors that continuously convert electrical energy into heat. Understanding these relationships is crucial for analyzing AC circuits and their components.
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Explain why a pure capacitor or a pure inductor does not consume electrical energy, while a pure resistor does. Illustrate your answer using waveform diagrams.

I need some wave diagrams for this. I have no idea what the waves look like
 
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For the inductor, draw the voltage and current waveforms versus time (assume sinusoidal excitation at some arbitrary frequency). What is the relationship between i(t) and v(t) for an inductor? What is the equation for the power consumed or supplied by an inductor? What is it net over a few periods of the sine wave?

Repeat for a capacitor and then a resistor. Show your work.
 
berkeman's post is excellent guidance, but I think I'll add a bit more detail.

Remember that reactive devices (like capacitors and inductors) have a phase shift between their V(t) and I(t) curves.

For example, the current through a capacitor is proportional to the time derivative of the voltage across it, correct?

I = C \frac{dV}{dt}

Well, that means if you put in a sine wave for V(t), I(t) must be a cosine wave -- a phase shift of ninety degrees.

Now, as berkeman says, find the instantaneous power consumed by the device by multiplying V(t) and I(t), and then integrate that over a period to find the average value.

- Warren
 

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