Acceleration and distance travelled questions

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The discussion revolves around calculating various aspects of a car's motion, including acceleration, distance traveled during acceleration, stopping time, and the increase in kinetic energy. The car accelerates from 36 km/h to 78 km/h in 6 seconds, prompting questions about the correct calculation of acceleration, which involves determining the change in velocity over time. Participants emphasize the importance of drawing a velocity-time graph to visualize the problem, noting that the area under the graph represents distance traveled. Additionally, they mention the need for specific equations relating displacement, velocity, and acceleration to solve the problem effectively. The conversation highlights the significance of understanding kinetic energy changes during different phases of motion.
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1. Homework Statement [/b
a car traveling at 36km/h accelerates to 78km/h in 6 seconds. the brakes are applied and the car stops in a distance of 120m, draw a v/t graph and workout

The rate of acceleration? i got 6km/h please correct if this is incorrect
The distance traveled during the acceleration stage?
The time to stop the car?
If the car has a mass of 900kg. determine the increase in kinetic energy?

Homework Equations





The Attempt at a Solution

 
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How about providing some of those equations? If you do that you'll be nearly done solving the problem.

Note that the units of acceleration are displacement/time^2. By how much does the velocity change per second? You accelerate from 36 km/h to 78 km/h in 6 seconds, so you can solve that easily.

If you draw the velocity curve over time, the area below it represents distance traveled, and the slop at any instance represents acceleration.

Else, there are three equations relating displacement, velocity, and acceleration. Those will answer the whole problem except the one about kinetic energy. You can look up that equation also.

"Increase" of KE implies two measurements at different times. Those could be from 36 to 78, from 78 to 0 or from 36 to 0. The latter two cases will yield a negative result.
 
for your solution of acceleration, you are numerically close, but still not quite correct
 
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