Acceleration and velocity involving calculus

AI Thread Summary
To find the instantaneous speed of a rocket described by the equation x = 10 + 5t^2, differentiate the equation with respect to time t, resulting in the velocity expression v = 10t. At 5 seconds, the instantaneous speed is calculated as v = 10(5), yielding 50 m/s. The acceleration, derived from the velocity expression, is constant at a = 10 m/s². All calculations are confirmed to be in the correct SI units. The analysis demonstrates a clear understanding of the relationship between position, velocity, and acceleration in calculus.
needhelp83
Messages
193
Reaction score
0
If the equation describing the motion of a rocket is
x = 10 + 5t^2, write an expression for the instantaneous speed of the rocket. What is the instantaneous speed at 5 s. What is the acceleration?


WHere do I begin? Do I need to take the integral anywhere?
 
Physics news on Phys.org
differentiate x = 10 +5t^2 with respect to t to get velocity and then differentiate your new velocity expression with respect to t to get the acceleration.

Given your expression for x your acceleration is going to be a constant.
 
Velocity
x=10+5t^2
Derivative with respect to t= 10t
Instantaneous speed of rocket=10t

Instantaneous speed at 5 s
v=10t
v=50 m/s
Would this be in the correct units?

Acceleration
a=10
 
yeah those are SI units so they are the correct units. Where the acceleration has units of \frac {m} {s^2}.
 
So if I am understanding this correctly...

The derivative of x=10+5t^2 with respect to t is the velocity
Expression for instaneous speed of rocket
V=10t

Instantaneous speed at 5 s
v=10t
v=10(5)
v=50 m/s

Acceleration is the derivative of velocity (v=10t) with respect to t
a=10
a=10 m/s^2

Look good?
 
Yup that looks fine.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top