Acceleration due to gravity - Help with equation. Thanks

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Homework Help Overview

The problem involves calculating the acceleration due to gravity (g) using the formula g = G Me/r^2, where G is the gravitational constant, Me is the mass of the Earth, and r is the radius of the Earth. The original poster expresses confusion about the calculation process.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss substituting values into the formula and question the correctness of their calculations. There are attempts to clarify the use of the gravitational constant and the proper handling of units and squaring the radius.

Discussion Status

Participants are actively engaging with the problem, with some providing guidance on how to approach the calculation. There are multiple interpretations of the results, and participants are checking their understanding against known values of g on Earth.

Contextual Notes

There is mention of potential confusion regarding the values and calculations, as well as the need to ensure accuracy in the results. The original poster expresses uncertainty about the calculations and seeks confirmation.

nukeman
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Homework Statement



Here is the problem:

GIven the formula below, calculate the expected value of the accerlation, G (in m/s^2). THe mass and radius of Earth are 5.974x10^24 kg and 6.37 x 10^6 m, respectively.

Formula to use: g = G Me/r^2

How do I solve for g ? I keep messing up on calculation.

Thanks


Homework Equations





The Attempt at a Solution

 
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'g' is already the subject of the formula, so you just need to substitute the numbers into the equation.
 
rock.freak667 said:
'g' is already the subject of the formula, so you just need to substitute the numbers into the equation.

Oh. So, it would then turn into:

g = G 5.974x10^24 / 6.37 x 10^6

?

So, would the answer be? 9.378x10^29

? That can't be rigbht
 
nukeman said:
Oh. So, it would then turn into:

g = G 5.974x10^24 / 6.37 x 10^6

?

So, would the answer be? 9.378x10^29

? That can't be rigbht

Well 'G' is a constant such that G=6.67300 × 10-11 m3kg-1s-2

And you are dividing by 106,so you can't really get back 1029. Redo the calculation with the value of 'G' in it.
 
rock.freak667 said:
Well 'G' is a constant such that G=6.67300 × 10-11 m3kg-1s-2

And you are dividing by 106,so you can't really get back 1029. Redo the calculation with the value of 'G' in it.

im real sorry, but you lost me with G

How do I do the calculation with Value G in it?
 
nukeman said:
im real sorry, but you lost me with G

How do I do the calculation with Value G in it?

g=GM/r2

Just replace the letters with the numbers given.
 
How do I calculate this? First, is this correct?

6.6726 x 10-11N-m^2/kg^2 x 5.974x10^24 / 6.37 x 10^6
 
nukeman said:
How do I calculate this? First, is this correct?

6.6726 x 10-11N-m^2/kg^2 x 5.974x10^24 / 6.37 x 10^6

Your units are the same throughout, so you can leave out the units in the calculation. You also forgot to square the radius 'r'.

g= (6.67x10-11)(5.974x1024)/(6.37x106)2
 
I tried it 2 diferent ways.

first answer: 9.37833595 x 10^24

next: 9.8200

??
 
  • #10
nukeman said:
next: 9.8200

This is more or less correct.
 
  • #11
rock.freak667 said:
This is more or less correct.

Is there anyway you can check, or I can be sure?

:)
 
  • #12
nukeman said:
Is there anyway you can check, or I can be sure?

:)

Well we know that on Earth, g=9.81 m/s2, so your answer should be around that number. (Depending on how accurate your values are)
 
  • #13
rock.freak667 said:
Well we know that on Earth, g=9.81 m/s2, so your answer should be around that number. (Depending on how accurate your values are)

Great, good enough for me :)

Thanks VERY much for your help, really appreciate it!
 

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