Acceleration in an Atwood's Machine

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SUMMARY

The discussion focuses on calculating the acceleration of masses in an Atwood's machine, specifically when the pulley has mass and radius. The correct formula for acceleration incorporates the moment of inertia of the pulley, defined as I = (1/2)M R² for a disk. The initial attempts to derive the acceleration were incorrect as they did not account for the pulley's mass. The final approach suggests treating the pulley as an added mass, simplifying the calculations.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with the concept of moment of inertia
  • Basic knowledge of rotational dynamics
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of acceleration in Atwood's machines with pulleys of varying mass
  • Learn about the moment of inertia for different shapes, focusing on disks and point masses
  • Explore the principles of rotational dynamics and their applications in mechanical systems
  • Practice solving problems involving multiple masses and pulleys in dynamics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of dynamics involving pulleys and mass systems.

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Homework Statement



An Atwood's machine consists of two masses, m1 and m2, connected by a string that passes over a pulley.
If the pulley is a disk of radius R and mass M, find the acceleration of the masses.
Express your answers in terms of variables m1,m2, M, R, and appropriate constants

Homework Equations




The Attempt at a Solution



I got the equation a=g*m1-m1/m1+m2 but it said this was incorrect because i need to function in M, the mass of the pulley. I am not sure how to incorporate that though.

I also tried a=g*m1-m2/m1+m2+I/r^2
it said this was incorrect also
 
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You need the moment of inertia of the pulley. For a disk it's 1/2M r^2 .
Note that for a point mass rotating around an axis the MoI is mr^2
A trick then is to treat the pulley as if it were a point mass with the same moment of inertia. You can then ignore the fact it rotates and treat it as an added mass.
 

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