Acceleration of a Cart Pulled by Different Forces

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The discussion focuses on calculating the acceleration of a 0.50 kg cart being pulled by a string over a pulley with a 0.25 kg mass hanging on the other end. Using g=10 N/kg, the tension in the string is determined to be 2.5 N, resulting in an acceleration of 5 m/s² for the cart when friction is absent. It is concluded that whether a student pulls the string with a force of 2.5 N or the 0.25 kg mass does, the acceleration remains the same due to the equivalent force generated. The analysis confirms that the tension in the string is consistent throughout, leading to identical acceleration outcomes. Thus, the method of pulling does not affect the acceleration of the cart.
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please help :) force question

Homework Statement



Use g=10 N/kg for this problem.
A 0.50 kg cart is on a level track. A horizontal string is pulling the cart. The string goes over a pulley and there is a 0.25 kg mass hanging at the other end.

a) What is the acceleration of the cart, if there is no friction>

b) Would the acceleration be different if there were a student pulling the string with a force of 2.5 N, rather than the 0.25 kg mass doing the pulling?

Homework Equations



T+(-mg)=ma

The Attempt at a Solution



for part B, i said it wouldn't matter because ultimately, 2.5 N=0.25 kg in this case because 2.5= 10*(m).
 
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The 0.25 kg mass hanging from the string pulley creates a tension T = m*g

T = 0.25 * 10 = 2.5N

The tension is the same all the way to the cart. As per the problem the cart has no friction.
So the cart weighing 0.5 kg is being moved by a force T = 2.5N

Acceleration is 2.5N/0.5 = 5m/sec^2

If a student pulled instead of the 0.25 kg mass, it would generate 2.5N force and the acceleration would be same.
 
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