Acceleration of a downhill skier

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The discussion focuses on the correct representation of the weight vector components for a downhill skier. The weight vector should be denoted as W, not -W, as the latter indicates the opposite direction. The x-component of the weight (Wx) should be parallel to the slope, while the y-component (Wy) is vertical. There is confusion regarding the signs of these components, with one participant noting that the y-component appears larger than the weight itself. Accurate diagram representation and understanding of vector direction are crucial for solving the problem correctly.
aron silvester

Homework Statement


I understand in my head that Wx = mgsin(27) and Wy = -mgcos(27). Though when I tried solving for both Wx and Wy, their signs turned out to be opposite. I've provided my work leading up to Wx = -mgsin(27) and Wy = mgcos(27). Maybe I interpreted the signs of x and y component of W?
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Homework Equations

The Attempt at a Solution


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The weight vector should be denoted ##\vec w##, not ##-\vec w##. The vector ##-\vec w## would point in the opposite direction of the weight.

Also, in you diagram, you drew ##\vec w_x## as horizontal rather than parallel to the x axis. (Note that your y component of the weight is larger than the weight w.)
 
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TSny said:
The weight vector should be denoted ##\vec w##, not ##-\vec w##. The vector ##-\vec w## would point in the opposite direction of the weight.

Also, in you diagram, you drew ##\vec w_x## as horizontal rather than parallel to the x axis. (Note that your y component of the weight is larger than the weight w.)
THANKS!
 
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