Acceleration of Charge in a Potential Gradient

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To determine the initial acceleration of a charged dust particle in a potential gradient, the potential function V(x) = (2.0V/m^2)x^2 - (3.0V/m^3)x^3 must be evaluated at x = 2.1m. The relevant equations include the relationship between potential energy and charge, as well as the formula for acceleration derived from force and mass. The discussion highlights confusion regarding the initial steps to solve the problem and emphasizes the need for applying the correct equations. Participants encourage providing a clearer attempt at solving the problem to facilitate better guidance. Understanding the potential gradient is crucial for calculating the particle's acceleration accurately.
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Homework Statement



A dust particle with mass of 0.043g and a charge of 2.0 * 10^(-6)C is in a region of space where the potential is given by V(x) = (2.0V/m^2)x^2 - (3.0V/m^3)x^3. If the particle starts at x = 2.1m, what is the initial acceleration of the charge? Your explanation will be extremely helpful. Thank you for taking the time to look at this question.


Homework Equations



Vba = (Ub-Ua)/q
dU = qVba
Vba = Vb - Va

V = (1/(4pieo))*(Q/r)

The Attempt at a Solution



I don't even know where to begin with this question.
 
Last edited:
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Where is your attempt at solving the problem? What about relevant equations?
 
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