Acceleration of rock due to gravity

WhyDidItakeIt
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A rock is dropped from rest at the top of a cliff 125 cm high.

a) At what speed does it strike the ground?

b) How long does it take?



To find the velocity the equation used is v = u + at

I know that (u = 0) as it's from rest and g = 9.81 ms (gravity)

But I just need help on how to get the velocity when the time is not stated!

I have the answers but I'm not sure how to reach them

a) 49.5 ms

b) 5.05 ms
 
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You have two options:

(1) Use conservation of energy

(2) Use another kinematic equation which involves velocity, distance and acceleration
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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