Acceleration of Spring Mass System - oneplusone

AI Thread Summary
In a spring mass system, at maximum amplitude, the velocity is zero while the displacement is at its peak. The acceleration is at its maximum magnitude at this point, calculated as -kx/m, where k is the spring constant and x is the displacement. The relationship between displacement, velocity, and acceleration can be visualized using sine functions, with velocity being the first derivative of displacement and acceleration being the first derivative of velocity. Understanding these relationships is crucial for solving AP multiple-choice questions related to spring mass systems. The discussion emphasizes the importance of grasping how acceleration behaves throughout the oscillation cycle.
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I always see those spring mass type questions on AP M.C. questions. Ones with a horizontal spring connected to a mass.
I understand that at the maximum amplitude, the velocity is zero since it is changing direction, and the displacement is maximum. However, what is the acceleration like? I can't seem to visualize it. Please help.

Cheers,
oneplusone
 
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Velocity is the first derivative of displacement and acceleration is the first derivative of velocity. If the displacement varies as a sin function, it's easy to calc velocity and acceleration. At max displacement, the magnitude of the acceleration is maximum and the velocity is zero.
 
oneplusone said:
I always see those spring mass type questions on AP M.C. questions. Ones with a horizontal spring connected to a mass.
I understand that at the maximum amplitude, the velocity is zero since it is changing direction, and the displacement is maximum. However, what is the acceleration like? I can't seem to visualize it. Please help.

Cheers,
oneplusone
At any displacement, the spring force is equal to the spring constant k times the displacement x. So the acceleration must be equal to -kx/m at all displacements.
 
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