Acceleration physics course work

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The discussion revolves around calculating the magnitude of a shell's acceleration just after being released by a glaucous-winged gull ascending at 5.40 m/s from a height of 13.5 meters. Participants initially attempt to apply kinematic equations but struggle with the correct setup. The key point is that the shell's acceleration immediately after release is equal to the acceleration due to gravity, which is approximately 9.81 m/s² downward. Clarifications emphasize the importance of using consistent units and the correct signs in calculations. Ultimately, the focus is on understanding the physics principles governing the motion of the shell post-release.
wadini
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A glaucous-winged gull, ascending straight upward at 5.40 , drops a shell when it is 13.5 above the ground. What is the magnitude of the shell's acceleration just after it is released?

x= -13.5 (because it is the same as when it went up but just negative)
v= 5.40

I got -.2 by putting in -5.40=2a(-13.5)...but that is not the right answer obviously...
 
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You may want to add units behind the numbers.
 


actually what i just realized is that I should probably plug in

-13.5=5.40+.5*a*...okay never mind
 


13.5m
5.40 m/s
 


A glaucous-winged gull, ascending straight upward at 5.40 m/s , drops a shell when it is 13.5m above the ground. What is the magnitude of the shell's acceleration just after it is released?
 

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