Calculating Acceleration of a Space Shuttle in Zero-Gravity Conditions

  • Thread starter Thread starter get_rekd
  • Start date Start date
  • Tags Tags
    Acceleration
AI Thread Summary
In zero-gravity, the space shuttle's thrust is 2.4 X 10^7 N, while its weight on Earth is 2.0 X 10^7 N. To find acceleration, the mass of the shuttle must first be calculated using the formula W = mg, resulting in a mass of 2.0 X 10^6 kg. The net force acting on the shuttle is equal to the thrust, allowing the calculation of acceleration using F = ma. Ultimately, the calculated acceleration of the shuttle is 12 m/s^2.
get_rekd
Messages
39
Reaction score
0
When the space shuttle is flying in space, away from the influence of any gravitational fields, its engines provide a total thrust of 2.4 X 10^7 N. If the shuttle weighs 2.0 X 10^7 N on the surface of the earth, what is its acceleration? (use g=10 m/s^2)

Fg= (2.0 X 10^7 N)(10 m/s^2)
= 2.0 X 10^8 N m/s^2

Fnet= (2.0 X 10^8 N m/s^2)-(2.4 X 10^7 N)
= 1.76 X 10^8 N m/s^2

a= 1.76 X 10^8

I have absolutely no clue how to do this but this is what I have figured out can someone please explain for me?
 
Physics news on Phys.org
If the shuttle WEIGHS 2 x 10^7 N on earth, then this is the force.

What you need to calculate is the mass of the shuttle using F = mg

The question states that it is away from the influence of any gravitational fields, so the net force is given by the thrust.

Using F = ma you can then determine the acceleration.
 
I'm sorry but I still don't understand.

so the mass of the shuttle would be 2 x 10^8 N then?
and Fnet= 2.4 X10^7?
 
hey, lol this looks awefully similar to a problem i have in my textbook.. but anyway
its like how he said, u have to remember that mass doesn't change, weight does. So in earth, you are given a weight. Therefore, you can find the mass of the shuttle. you see

W=mg (use 10 for your g), then once you have that..use F(thrust)= ma

simple heh
 
mass of the shuttle is in KG, and force is in NEWTONS (N), it is important to get the units right..
 
OK... If something weighs 2 x 10^7 N, then this is the force with which gravity is pulling it towards Earth.

Its mass can be determined from a rearrangement of F= mg (mass is measured in kg)

Now, if we have a mass shooting through space, being pushed by an engine with a force of 2.4 x 10^7 N, we can figure out its acceleration using a rearrangement of F = ma.


Note that these are two different cases, so the F in each is different.
 
right, use W=mg, because well its not wrong technically, but weight is a force, and in physics you generally use W for weight instead of Fg. anyway tell me what u get
 
and remember the mass doesn't change
 
I think my head is all goofed up today I just can't seem to do math correctly haa..

So I would then take,
2.4 X 10^7 N = (2.0 X 10^8 N)(a)
-2.0 X 10^8 N -2.0 X 10^8 N
-1.76 X 10^8 N = a??
 
  • #10
lol, atleast you realized that is wrong.. but look acceleration is (m/s^2) force is (kg m/s^2) aka: mass x acceleration. anyway lol
2.0x10^7 N= mg (10=g)
then take that mass
2.4x10^7N=ma (a is what you solving for) if i do anything more, i will end up solving the problem
 
  • #11
Not quite.

Your 2.0 x 10^8 is wrong.

W = mg

2.0 x 10^7 = m (10)

m=?

then use F(thrust) = ma
 
  • #12
okay so then...
2.0 X 10^7 = m(10)
-10 -10
1.9 X 10^7 = m

2.4 X 10^7 N = 1.9 X 10^7(a)
-1.9X10^7N -1.9X10^7N

5.0 X 10^6 N = a
 
  • #13
You are subtracting where you need to divide. - do the calculations again.

Other than that it looks ok.

Also, remember your units! acceleration is measured in m/s^2
 
  • #14
LOL! sorry, not to be mean, but that was funny
 
  • #15
alright so. For the 8th try haha! 2.4 X 10^7 N = 1.9 X 10^7 N a
then I divide 2.4 X 10^7 N by 1.9 X 10 ^7 N and get a
so a = 1.3 m/s^2
 
  • #16
nope.. i don't know what to say lol,
 
  • #17
okay so then...
2.0 X 10^7 = m(10)
-10 -10 (ERROR)-- fix that
1.9 X 10^7 = m (fix that)

2.4 X 10^7 N = 1.9 X 10^7 (fix that) (a)
-1.9X10^7N -1.9X10^7N (DIVIDE not multiply) 6=2x3 --> 3=6/2 or 2=6/3 (6-3 doesn't = 2-3)

5.0 X 10^6 N = a
 
  • #18
Thanks a lot for the help guys. I appreciate it!
 
  • #19
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #20
good lol :)
 
  • #21
finally! thank you so much for your patience and your help guys.
 
  • #22
alright I think I figured it out now I hope to the lord.

2.0 X 10^7 N = m(10)
------------ -------
10 10

m= 2.0 X 10^6 N (should be Kg) just saying because if u are writing this problem down, i don't want you to get points off for that.

2.4 X 10^7N = 2.0 X 10^6 N a
------------- ---------------
2.0X10^6N 2.0X10^6N

a= 12 m/s^2
 
  • #23
okay thank you.
 
Back
Top