Acceleration using kinetic friction

AI Thread Summary
A block on an 18.8° slope is connected to a 2.97 kg hanging block, with static and kinetic friction coefficients provided. The minimum mass M1 required to prevent slipping was calculated to be 3.27 kg. For Part B, the user is seeking to determine the acceleration of M1 when nudged slightly, using the equation m1a + m2a = m2g - m1gsin(theta) - ukm1gcos(theta). There is confusion regarding the direction of the pull, whether it is uphill or downhill. Clarification on the setup and correct application of the formula is needed to find the acceleration.
joedozzi
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Part A: A block of mass M resting on a 18.8° slope is shown. The block has coefficients of friction μs=0.620 and μk=0.314 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.97 kg. What is the minimum mass M1 that will stick and not slip?

I have figured this part out.. the mass is 3.27kg

Now I need this mass in order to complete this question
Part B: If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?

I tried using this equation and plugged in all my variables but I must be missing something.

Formula: m1a + m2a = m2g - m1gsin(theta) - ukm1gcos(theta)
 
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hi joedozzi! :smile:

(have a mu: µ and a theta: θ and try using the X2 icon just above the Reply box :wink:)
joedozzi said:
Part A: A block of mass M resting on a 18.8° slope is shown. The block has coefficients of friction μs=0.620 and μk=0.314 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.97 kg. What is the minimum mass M1 that will stick and not slip?

Formula: m1a + m2a = m2g - m1gsin(theta) - ukm1gcos(theta)

looks ok to me :confused:

(that's for being pulled uphill … is this uphill or downhill?)
 
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