Acceleration when time is not given

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Homework Help Overview

The discussion revolves around a problem involving the acceleration of a cyclist who comes to a stop over a certain distance. The cyclist's initial velocity, mass, and stopping distance are provided, raising questions about how to calculate acceleration without direct time information.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various equations of motion, particularly focusing on the relationship between velocity, distance, and acceleration. There is a discussion about whether mass is relevant in this context and how to properly convert units for calculations.

Discussion Status

Some participants have attempted calculations using different formulas and have raised questions about unit conversions. There is acknowledgment of errors in initial calculations, and one participant indicates they have found the correct answer after revisiting their work.

Contextual Notes

Participants discuss the necessity of converting velocity from km/hr to m/s for consistency in SI units. There is also mention of the validity of certain equations under specific conditions, particularly regarding constant velocity assumptions.

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1. A cyclist traveling 21km/hr stops over a distance of 15m. His total mass is 73kg. What is his acceleration?



2. T=D/V, A=V/t



3. Since time is displacement over velocity, I can use the displacement and velocity to find time and then solve acceleration by a=v/t. Am I on the right track or should the mass have come into play there?
 
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[tex]V_f^2=V_i^2+2ax[/tex] would work?
 
PhysicsAdvice said:
3. Since time is displacement over velocity, I can use the displacement and velocity to find time and then solve acceleration by a=v/t. Am I on the right track or should the mass have come into play there?

No-

x = vt

...is only valid when v is constant, which it is not.
 
I tried [tex]V_f^2=V_i^2+2ax[/tex] which comes to
0=441+2a (225),
-441/225=2a,
-1.96=2a,
-0.98=a

but the answer is -1.1, error?
 
PhysicsAdvice said:
I tried [tex]V_f^2=V_i^2+2ax[/tex] which comes to
0=441+2a (225),
-441/225=2a,
-1.96=2a,
-0.98=a

but the answer is -1.1, error?

I'm not sure what units you're using? Convert everything to SI units (velocity in m/s, distance in m) and it turns out fine.
 
vi=21km/hr vf=0km/hr distance=15m, so do i need to convert the 21km/hr to m/s?
 
nevermind I tried it again and found the right answer, thanks!
 

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