What is the pH of solutions containing (CH3)3N+Cl- and (CH3)4N+Cl-?

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The discussion revolves around the acidity or neutrality of two compounds when dissolved in water. The first compound, (CH3)3N+Cl-, is identified as slightly acidic due to the presence of a protonated weak base, (CH3)3NH+, which acts as a weak acid. The second compound, (CH3)4N+Cl-, is deemed neutral. A clarification is made regarding the first compound, emphasizing the importance of the cationic component in determining acidity. The conversation also references a previous discussion on the topic, indicating ongoing interest in the behavior of these compounds in solution.
nautica
Acidic, Basic, or nuetral?

If each was dissolved in water, will the solution be acidic, basic, or neutral?

1) (CH3)3N+Cl- Acidic
2) (CH3)4N+Cl- Nuetral

Are these right?

Thanks
nautica
 
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Sorry, I couldn't find it and could not remember what we had decided. Thanks

On the other I had a typo. It should be

(CH3)3NH+Cl-
 
Okay, that one should be slightly acidic. A protonated weak base will be a weak acid.
 
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