Action reaction problem or Newton's 3 law

AI Thread Summary
The discussion centers on identifying the forces acting on block B, which is stationary due to friction with block A. Key forces include the upward normal force from the floor, the downward gravitational force from Earth, and frictional forces acting to the left and right due to block A's interactions. Newton's third law is emphasized, highlighting that action and reaction forces act on different objects. The net force on block B must be zero, confirming its stationary state. The participants clarify the nature of friction as both a reaction force and a stabilizing force in this context.
astrololo
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Homework Statement



There is a bloc B that is on a surface S. A bloc A is on on the bloc B. We pull the rope towards the right. There is friction between all surfaces and the blocs stay stationary (They don't move). Identify all the forces which are applied on the bloc B.
http://imgur.com/Hzgc8pP

Homework Equations



No equations.

The Attempt at a Solution



I know that there is going to be a Normal upward, another normal that is downward because it is a reaction according to Newton's third law, the gravitational force downward. I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A. Now, I don't know what else to find... There is one missing...

Here is another image http://imgur.com/FYWfLgE[/B]
 
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Consider any pair of Newton's Third Law action/reaction forces. The two forces never act on the same object.

So, for example, Block A pushes down on Block B, and Block B pushes up on Block A.
 
Mister T said:
Consider any pair of Newton's Third Law action/reaction forces. The two forces never act on the same object.

So, for example, Block A pushes down on Block B, and Block B pushes up on Block A.
Yes but I don't see what else I can get... I'm only interested in object B and I got one pair of normal forces on the bloc A and B.
 
Draw a diagram showing only Block B. On the diagram indicate only the forces that are acting on Block B.
 
Mister T said:
Draw a diagram showing only Block B. On the diagram indicate only the forces that are acting on Block B.
I know that there is going to be a Normal upward, another normal that is downward because it is a reaction according to Newton's third law, the gravitational force downward. I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A.http://imgur.com/T9RXe3F
 
astrololo said:
I know that there is going to be a Normal upward,

Exerted by the table.

another normal that is downward

Exerted by Block A

because it is a reaction according to Newton's third law,

(Every force is a reaction according to Newton's Third Law!)

the gravitational force downward.

Exerted by Earth.

I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A.

Exerted by Block A.

And one more ...

Hint: The net force on Block B must be zero because Block B is not in motion.
 
Mister T said:
Exerted by the table.
Exerted by Block A
(Every force is a reaction according to Newton's Third Law!)
Exerted by Earth.
Exerted by Block A.

And one more ...

Hint: The net force on Block B must be zero because Block B is not in motion.
Oh, there's a friction force to the left because if there wasn't one, then the block B would be moving, right ? So it's not a reaction but more of a "stabilizer", right ?

Also, when I said "I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A." and you said : "Exerted by Block A." You mean that the block A is responsible for this reaction to the right, right ?
 
astrololo said:
Oh, there's a friction force to the left because if there wasn't one, then the block B would be moving, right ? So it's not a reaction but more of a "stabilizer", right ?

Table pushes to the left on Block B, Block B pushes to the right on Table. It's an action/reaction pair. We call it friction.

Also, when I said "I think that there is going to be a friction force on the right because it is a reaction to the friction of bloc A." and you said : "Exerted by Block A." You mean that the block A is responsible for this reaction to the right, right ?

Correct!

Block A pushes to the right on Block B, Block B pushes to the left on Block A. It's an action/reaction pair. We call it friction.
 
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Mister T said:
Table pushes to the left on Block B, Block B pushes to the right on Table. It's an action/reaction pair. We call it friction.
Correct!

Block A pushes to the right on Block B, Block B pushes to the left on Block A. It's an action/reaction pair. We call it friction.
Just one thing, the "S" isn't a table but a floor.

Forget it I understood what you meant Thanyou!
 
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