Adding a mass on an oscillation causing a change in frequency

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Homework Help Overview

The problem involves a thin uniform rod oscillating with a certain frequency, and the effect of adding a mass at the other end on that frequency. The context suggests a relationship to oscillatory motion, potentially resembling pendulum behavior.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of adding mass on the frequency of oscillation, with some questioning the relationship between potential energy, kinetic energy, and frequency. There is uncertainty about whether the scenario relates to a pendulum and what factors influence frequency.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the relevance of mass in the frequency equation for a pendulum, but no consensus has been reached on the overall impact of the added mass on frequency.

Contextual Notes

Participants are grappling with the definitions and relationships between energy types and frequency, as well as the specific characteristics of pendulum motion. There is a lack of clarity on how these concepts interrelate in the context of the problem.

kavipach
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Homework Statement


A thin uniform rod of mass m is suspended from one end and oscillates with a frequency f.
If a small sphere of mass 2m is attached to the other end, does the frequency increase or decrease?

Homework Equations





The Attempt at a Solution


I have reached a conclusion that the frequency would decrease but I am not sure exactly why. Is it because the amplitude would become bigger?
 
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No, it's not because of the amplitude.

Is this talking about a pendulum? What do you know about pendulums? Any formulas?
 
i know that pendulums work due to the concervation of energy but i don't understand how this could be about a pendulum.
 
Unless the P.E becomes greater when mass and since P.E=K.E, K.E becomes greater. But i don't understand how this would change the frequency.
 
kavipach said:
Unless the P.E becomes greater when mass and since P.E=K.E, K.E becomes greater. But i don't understand how this would change the frequency.

What can you say about the period of a pendulum?
 
kavipach: What is the equation for frequency of a pendulum?

If you look closely, there are only two variables in that equation. Is mass one of them?
 

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