(adsbygoogle = window.adsbygoogle || []).push({}); 1. If the problem statement, all variables and given/known data

The resultant force acting is directed along the positive x-axis, determine the magnitudes of F2 and the resultant force

And that F3x=4 and that F3y=3 (its a right angle 3-4-5 triangle)

2. Relevant equations

F1=F1_{x}+F1_{Y}

F2=F2_{x}+F2_{Y}

F3=F3_{x}+F3_{Y}

3. The attempt at a solution

F1y= 4cos(30) = 3.464

F3y=3

And since the resultant force is along the x-axis, the resultant y force (Fr_{y}) would therefore have to equal 0.

But when you run the numbers:

Fr_{y}=F1_{Y}+F2_{Y}+F3_{Y}

Fr_{y}=(+3.464)N + (-3)N + F2_{y}

F2_{y}= -0.464

xsin30=-0.464

x=-0.464/sin30

x=-0.928

But that is impossible because F2 is above the x-axis and therefore couldn't have a negative y value.

This is where I am currently stuck, if it would work out i could figure out the resultant of F2_{y}and F2_{x}which would be F2, and the find out the resultant of all three from there on.

Thank you in advance,

Chris

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# Homework Help: Addition of a System of Coplanar Forces

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