Addition of angular momentum - Finding the second tower states

AI Thread Summary
The discussion focuses on calculating the states for a quantum system with angular momentum values l=1 and s=1/2, specifically finding the second tower states for j=1/2. The user has successfully computed the states for j=3/2 but is struggling with the j=1/2 states, particularly |j,j_z>=|1/2, 1/2>. They recognize that the state must be orthogonal to the known state |3/2, 1/2> and are unsure how to express it in terms of l_z and s_z to find the Klebsch-Gordon coefficients. The conversation highlights the importance of orthogonality in quantum states and the need to sum or combine states appropriately. The user is encouraged to keep orthogonality in mind as they continue their calculations.
DataGG
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Homework Statement



I'm supposed to calculate all the states for a system with ##l=1## and ##s=1/2##. Let's say ##\vec{J} = \vec{L} + \vec{S}##. I want to find the Klebsch-Gordon coefficients.

I know that said system has 2 towers, one with ##j=3/2## and the other with ##j=1/2##. I've calculated all the states for ##j=3/2## but now I'm having some problems with ##j=1/2##.

So, for the second tower, we've two states: ##|j,j_z>=|1/2, 1/2>## and ##|j,j_z>=|1/2, -1/2>##

How am I supposed to find ##|j,j_z>=|1/2, 1/2>##? If I do that, finding ##|j,j_z>=|1/2, -1/2>## should be easily done by applying the ##J _## operator.

Homework Equations



$$J _ |j, j_z>=\hbar \sqrt{j(j+1)-j_z(j_z-1)}|j,j_z-1>$$
$$S _ |s, s_z>=\hbar \sqrt{s(s+1)-s_z(s_z-1)}|s,s_z-1>$$
$$L _ |j, j_z>=\hbar \sqrt{l(l+1)-l_z(l_z-1)}|l,l_z-1>$$

The Attempt at a Solution



Well, I've done well for the tower with ##j=3/2##. Now with this second tower, I don't know where to begin from. I think this is because for ##j = j_z = 3/2##, we know that ##j_z = l_z + s_z## which means ##l_z =1 ## and ##s_z = 1/2##. There's no other way.

For the case with ##j=1/2##, we've two options. ## l_z=0, s_z=1/2##, which is to say ##|l_z,s_z>=|0, 1/2> ## and ##l_z=1, s_z=-1/2##, which is to say ##|l_z,s_z>=|1, -1/2>##. Should I sum those states somehow?
 
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You already know that one of the jz = 1/2 states is part of the j=3/2 representation. Since there are only two of those, which is the remaining one?
 
Orodruin said:
You already know that one of the jz = 1/2 states is part of the j=3/2 representation. Since there are only two of those, which is the remaining one?

I'm not sure I understand what you're saying.. I know that, for ##j_z = 1/2## there's two states. One being for ##j=3/2## and the other for ##j=1/2##. That is:

##|j, j_z> = |3/2, 1/2>## and ##|j, j_z> = |1/2, 1/2>##. Now I need to write this last state using ##l_z## and ##s_z##, in order to find the Klebsch-Gordon coefficients.
 
Yes, I am fully aware of that. What I am saying is that you know what the state with ##j_z = 1/2## and ##j = 3/2## is, since you have already computed the states with ##j = 3/2##. The state you are searching for must be orthogonal to this.
 
Orodruin said:
Yes, I am fully aware of that. What I am saying is that you know what the state with ##j_z = 1/2## and ##j = 3/2## is, since you have already computed the states with ##j = 3/2##. The state you are searching for must be orthogonal to this.

Oh! I forgot that. I don't know why they need to be orthogonal though, but I guess that's a discussion for another thread. I'll see if I can solve it having that in mind!

Thank you Orodruin!
 
DataGG said:
I don't know why they need to be orthogonal though

What can you say about the operator ##\hat J = \hat L + \hat S##?
 
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