Addition of exponentials, and relationship between variables.

AI Thread Summary
The discussion centers on the relationship between the variables w and q in the equation Exp[-i*q*t] + Exp[-i*w*t] = -2. The solution involves converting the exponentials into trigonometric functions and utilizing sum-to-product formulas, leading to the conclusion that w/q = (2m-1)/(2n-1) for positive integers m and n. It is noted that for the exponentials to sum to -2, both must equal -1, implying specific conditions on their angles. The conversation also highlights that if q and w can be imaginary, a broader range of solutions exists. Overall, the geometric interpretation of the problem emphasizes the impossibility of forming a triangle with sides of length 1 that results in a total length of 2.
Animastryfe
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Homework Statement


This is, strictly speaking, not a homework question. I have already solved this, but I think that there is a much better method to solve it.

In the equation below, what relationship must w and q satisfy? If the question is not clear, please read the bottom of the post.

Homework Equations


Exp[-i*q*t]+Exp[-i*w*t]=-2


The Attempt at a Solution


I turned everything into cosines and sines, and used the trigonometric sum to product formulas.

In case the question isn't clear, the answer is w/q= (2m-1)/(2n-1), where m and n are positive integers and not equal to each other.
 
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Hi Animastryfe! :smile:

Assuming q and w are real numbers, the two exponentials each correspond to a vector with length 1 and angle -qt respectively -wt.
This is the polar coordinate representation of a complex number.

To get them to have sum -2, both the exponentials must come out as -1.
This means that -qt = pi mod 2pi and that -wt = pi mod 2pi.
Divide them on each other and you get the result you have.

However, if q and w can be imaginary as well, you get a lot more solutions! :wink:
 
Thank you. I should think more geometrically.
 
Please note that, in general, for two complex numbers to add to -2, they do not have be each be -1. Here, however, each has magnitude 1 so in terms of a vector addition, we have a "triangle" with two sides of length 1 and the third of length 2. That, of course, is impossible except in the very special case that the "triangle" is really a straight line.
 
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