Adiabiatic Process: q=0 & Work Done Path Function?

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In an adiabatic process, where heat transfer (q) is zero, the change in internal energy equals the work done. Internal energy is a state function, leading to the question of why work differs between reversible and irreversible adiabatic processes. The distinction arises because irreversible processes do not maintain thermodynamic equilibrium at intermediate states, making the concept of a path function inapplicable. Thus, while internal energy remains a state function, the work done is affected by the nature of the process. The discussion emphasizes the importance of thermodynamic equilibrium in defining work in adiabatic processes.
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In an adiabiatic process q=0 so change in internal energy become equal to work. Since internal energy is path function so work done in an adiabiatic process should also be path function then why work done in adibiatic reversible and irreversible different?
 
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Rachit Garg said:
internal energy is path function so work done in an adiabiatic process should also be path function

This assumes that every state traversed by the process is a thermodynamic equilibrium state. Out of thermodynamic equilibrium, the concept of a "path function" is not well-defined.

Rachit Garg said:
why work done in adibiatic reversible and irreversible different?

Because in an irreversible process, the intermediate states are not in thermodynamic equilibrium.
 
By mistake i have wriitten that i want to say In an adiabiatic process q=0 so change in internal energy become equal to work. Since internal energy is state function so work done in an adiabiatic process should also be state function then why work done in adibiatic reversible and irreversible different?
 
Rachit Garg said:
By mistake i have wriitten that i want to say In an adiabiatic process q=0 so change in internal energy become equal to work. Since internal energy is state function so work done in an adiabiatic process should also be state function then why work done in adibiatic reversible and irreversible different?

This is basically the same question you asked in your OP, and I answered it in post #2. (My answer is still valid if you substitute "state function" for "path function".) Do you have questions about my answer?
 

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