Adv. function work problem(polynomialf)

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Homework Statement




Two soccer players start at opposite sides of an 80-m field. One runs at 4m/s and the other runs at 5m/s. If they run back and forth for 15 min how many times will they pass each other?


Does anyone know how to solve this?





Homework Equations





The Attempt at a Solution



I tried this one, did 80/4 to get distance ran, then divided that by 900s to get amount of times ran from the track.

900s / 20 laps is 45.

I think that's right, buti don't know where to go from there. What do i do with the second runner? It doesn't work out, any hints, help etc.. please very urgent
 
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If the answer isn't readily apparent, draw a diagram. How many meters will the 4ms runner cover in 15 minutes? How many will the 5ms runner cover?

Now plot the position of the two runners. For example, where are the two runners after 5 seconds? 6 seconds? 7? How about after 10 seconds? Have they passed each other yet? If so, at what time did they pass. Be specific.

Then keep plotting until you discover the second instance of passing. Note the time it occurs. After 3 or 4 passings you'll see the pattern.

Then the formula should become apparent.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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