After how many time constants is capacitor energy 1/4?

AI Thread Summary
The discussion focuses on determining the time required for a discharged capacitor's energy to reduce to one-fourth of its initial value. The correct approach utilizes the energy formula U = Q²/2C, leading to the conclusion that t = 0.693RC after one time constant. An initial attempt using a different equation led to confusion regarding the relationship between charge and voltage. The error was identified as a misunderstanding of the changing voltage (ε) during discharge, which is not constant. The thread emphasizes the importance of correctly applying equations based on the capacitor's state during discharge.
David Day
Messages
12
Reaction score
1

Homework Statement


[/B]
After how many time constants
is the stored energy of a discharged capacitor one-fourth its initial value?

Homework Equations


[/B]
(1) U = Q2/2C

(2) U = Qmaxε/2

(3) q(t) = Qie-t/RC

The Attempt at a Solution



The solution can be correctly attained using the first equation:

(1/4) Q2/2C = (Qie-t/RC)2/2C

(1/4) = e-2t/RC

t = 0.693RC

However, I first attempted to use equation (2) but could not get the correct answer. I can't figure out what mistake or incorrect assumption I'm making. My attempt follows:

(1/4) Qmaxε/2 = Qmaxe-t/RCε/2

(1/4) = e-t/RC

As can be seen here, this answer is off from the first by an exponent of two. Q2/2C and Qmaxε/2 are mathematically equivalent, so I'm not sure where I'm making the error. Is it not correct to assume Qmax = Qi?

I'd really appreciate some help in clearing this up!

EDIT: I may see my problem. The ε in equation (2) is proportional to Q and will thus be changing, i.e, it's not equal to the ε on the other side of the equation except when t = 0, so I need to change it to Q/C, which will be the same form as equation (1). I'm not sure if this is the problem or not...
 
Last edited:
Physics news on Phys.org
David Day said:
After how many time constants
is the stored energy of a discharged capacitor
Do you mean a "discharging" capacitor?
David Day said:
(1/4) Qmaxε/2 = Qmaxe-t/RCε/2
If the capacitor is discharging, can you use the same ε on the RHS of this equation as in the LHS?

Edit: I see you found the error in your equation by yourself while I was typing my response. Well done!
 
Last edited:
  • Like
Likes David Day
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top