After two time constants of time have elapsed, the current in the circ

AI Thread Summary
After two time constants have elapsed in an RC circuit, the current is approximately 0.135 times the final steady-state current. The time constant, denoted as τ, is crucial in analyzing how quickly a circuit responds to changes, particularly in circuits with capacitors. This discussion emphasizes the need for understanding time constants in relation to charging and discharging processes. Clarification on the specific circuit type and components involved would enhance the discussion. Understanding these concepts is essential for accurate circuit analysis.
TravisBoyd
Messages
2
Reaction score
0
After two time constants of time have elapsed, the current in the circuit is how many times the final current?
 
Physics news on Phys.org
?I think you need to clarify, as I have no idea what you're talking about.
 
TravisBoyd said:
After two time constants of time have elapsed, the current in the circuit is how many times the final current?

You're going to need to show at least some kind of effort to solve this. Tell me, what's a time constant? When do we use it in a circuit?
 
Does this involve caps and time dependant analysis? Or can you clue me in as to the subject or topic of this question?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Current through an inductor as a function of time
Replies
10
Views
311
What is the maximum current in a RL circuit using V=IR?
Replies
13
Views
2K
Two concentric conducting spherical shells and resistor in between
Replies
44
Views
4K
Finding Current in Resistors & Charge of Capacitor
Replies
4
Views
2K
Find current through inductor after many time constants.
Replies
2
Views
3K
Roller coaster mock Lab Report
Replies
9
Views
634
Calculating Friction & Time for a Bullet Penetrating Rubber
Replies
2
Views
1K
Net force between two conducting strips
Replies
6
Views
797
Current flowing in an open circuit
Replies
9
Views
1K
Symmetrical parallel inductors, different currents? State Preparation
Replies
7
Views
1K

Hot Threads

Recent Insights

Back
Top