Air is made up of only 2 gases oxygen and nitrogen

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Air is primarily composed of oxygen and nitrogen, with a molecular mass of 29 g/mol. The atomic weights for oxygen and nitrogen are 16 g/mol and 14 g/mol, respectively. The correct percentage composition by mass is approximately 72.4% nitrogen and 27.6% oxygen. The confusion arises from whether the percentages are calculated by weight or number of molecules, as the initial calculations led to incorrect negative percentages. Ultimately, the final mass percentages align closely with the accepted values, confirming the calculations using molar masses.
Dell
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if air is made up of only 2gases oxygen and nitrogen, and the molecular mass of air is 29g/mol, find the % of each component in the air,

what i thought i should do is make 2 equations,

Mw(O)=16
Mw(N)=14

X*16 + Y*14 = 29 (in 1mol of air)
X + Y = 1

but the solution to this is not possible, i get one as a negative pct

the correct answer is meant to be
72.5%
27.5%
 
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Dell said:
Mw(O)=16
Mw(N)=14

These are atomic weights, not molecular weights.
Remember oxygen and nitrogen are both diatomic gases.
 


thanks, so my equations would go

X*2*16 + Y*2*14 = 29 (in 1mol of air)
X + Y = 1


then i get 75%, 25%
is this correct? the "correct" answer in my book is 72.5% 27.5%
 


Is that 72.5% by weight, or by number of molecules?
 


it actually doesn't say, never thought of that,

is what i got by mol;ecules? how would i make the conversioin
 


got it,,

0.75*28=21g
0.25*32=8g

8/29=27.6%
21/29=72.4%

close enough
 


25% and 75% is a correct answer using 28, 32 and 29 as molar masses and assuming final result must be just molar fraction.

27.6% and 72.4% is a correct answer in terms of mass percentage.


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