Air Pressure and Water Pressure

AI Thread Summary
To determine the depth in a freshwater lake where the water pressure is 4.5 atm, it's essential to account for the atmospheric pressure at the surface, which is 1.1 atm. The total pressure at the desired depth is 4.5 atm, meaning the gauge pressure needed is 4.5 atm - 1.1 atm = 3.4 atm. Converting this gauge pressure to Pascals gives 340,000 Pa. Using the equation Pguage = Dgh with the density of water (1000 kg/m³) and gravitational acceleration (9.8 m/s²), the correct depth can be calculated as h = 340,000 / (1000 * 9.8), resulting in approximately 34.7 meters. This adjustment clarifies the misunderstanding regarding the use of gauge versus absolute pressure.
vrobins1
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Homework Statement



"At the surface of a freshwater lake the air pressure is 1.1 atm. At what depth under water in the lake is the water pressure 4.5 atm?"



Homework Equations



I used the equation Pgauge = Dgh



The Attempt at a Solution



I converted my atm to Pascals--> (4.5)(100000) = 450000 Pa
Pguage = Dgh
Pguage = (1000)(9.8)(h)

-I used 1000, the density of water, but I'm not sure that is the right info to use for D!

Then I solved for h.

h = 450000/ (10000x9.8)
h = 45.92
I got it incorrect though. Can anyone offer any insight? Thanks!
 
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vrobins1 said:

Homework Statement



"At the surface of a freshwater lake the air pressure is 1.1 atm. At what depth under water in the lake is the water pressure 4.5 atm?"



Homework Equations



I used the equation Pgauge = Dgh



The Attempt at a Solution



I converted my atm to Pascals--> (4.5)(100000) = 450000 Pa
Pguage = Dgh
Pguage = (1000)(9.8)(h)

-I used 1000, the density of water, but I'm not sure that is the right info to use for D!

Then I solved for h.

h = 450000/ (10000x9.8)
h = 45.92
I got it incorrect though. Can anyone offer any insight? Thanks!
That would have been OK if the problem asked for the gauge pressure. I think it's looking for the depth at an absolute pressure of 4.5 atm, which includes the atmospheric pressure.
 
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