Air pressure needed for ballast

AI Thread Summary
To blow water out of a submarine's ballast tanks at a depth of 3150 ft in the Atlantic Ocean, an air pressure of 9410 kPa is required. The calculation involves using the formula P = ρgh, where ρ is the seawater density, g is the gravitational acceleration, and h is the depth in meters. A conversion from feet to meters is necessary, as well as accounting for atmospheric pressure. A common mistake in calculations includes using incorrect values for gravitational acceleration. Understanding unit conversions is crucial for accurate pressure calculations in this context.
doodles
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A submarine is submerged to a depth of 3150 ft in the Atlantic Ocean. What air pressure (in kpa) is needed to blow water out of the ballast tanks?

I know the answer is 9410 kpa but I have been going in circles trying to figure this out.

P=hd using seawater density of 64.0 pound feet cubed did not work for me.

Thanks for helping:)
Doodles
 
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Let's work in metric units. P=rho*g*h, and you know all three variables, so you can find P. That's the pressure exerted by the water. You have to add on the pressure exerted by the atmosphere, and that's your answer.
 
Thanks Ideasrule:smile:

P=1000kg/m^3(9.801m/s^2)(3150ft)(1/3.281ft)=9409676.928 pascals= 9410kpa

I made a mistake and was using 9.81m/s^2 instead of 9.801m/s^2

I still can't figure out how I got pascals out of kg/m^3 s^2 any suggestions? These type of conversions get tricky.
 
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