Al(OH)3 as an electrolyte. What does it produce?

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The discussion centers around the electrolysis of a solution of Aluminum Hydroxide using direct current. A solid precipitate is forming at the negative terminal, while bubbles are observed at both terminals, indicating hydrogen at the negative and oxygen at the positive terminal. The positive terminal is experiencing corrosion, evidenced by tiny holes. Participants suggest that the solid could be Aluminum Oxide, with some clarification needed on its correct form, which is typically Al2O3 rather than AlO2. The process is linked to the anodization of aluminum, where aluminum reacts with water to form aluminum oxide and release hydrogen ions and electrons. The use of aluminum electrodes is confirmed, and additional resources are shared for further reading on the topic.
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I am running a dc current through a solution of Aluminum Hydroxide and I see a solid precipitating from the negative terminal, and bubbles coming from both terminals. Also, the positive terminal is corroding with little tiny holes in it. What is the solid being produced, and what is happening to the positive terminal. I know that the bubbles are hydrogen at the negative terminal, and oxygen at the positive terminal. I suspect that the solid is Aluminum Oxide, but I cannot find much proof through research.
 
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gabede said:
I am running a dc current through a solution of Aluminum Hydroxide and I see a solid precipitating from the negative terminal, and bubbles coming from both terminals. Also, the positive terminal is corroding with little tiny holes in it. What is the solid being produced, and what is happening to the positive terminal. I know that the bubbles are hydrogen at the negative terminal, and oxygen at the positive terminal. I suspect that the solid is Aluminum Oxide, but I cannot find much proof through research.

Do you use dissimilar electrode? What electrodes are you using?
Probably yes, its AlO2. Reaction could be this Al(OH)3→H+1/2O2+AlO2
 
Ronie Bayron said:
Do you use dissimilar electrode? What electrodes are you using?
Probably yes, its AlO2. Reaction could be this Al(OH)3→H+1/2O2+AlO2
Are you sure about that form for aluminum oxide? It's common, stable form is Al2O3.
 
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I used two aluminum electrodes.
 
Redbelly98 said:
Are you sure about that form for aluminum oxide? It's common, stable form is Al2O3.
Yes, my bad. That could also be the case. I think you are right about it.
It's called Anodization of aluminium (page 5 of 11)
 
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gabede said:
I used two aluminum electrodes.
Read through here: http://people.uleth.ca/~roussel/C1000/slides/12group13metals.pdf
 
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